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A wave traveling in a string in the positive x direction has a wavelength of 35 cm, an amplitude of 8.4 cm, and a period of 1.2 s. What is the wave equation (in base SI units) that correctly describes this wave

1 Answer

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Step-by-step explanation:

It is given that,

Wavelength of a wave,
\lambda=35\ cm=0.35\ m

Amplitude,
A=8.4\ cm

Period of the wavelength, t = 1.2 s

The wave is traveling in a string in the positive x direction. We need to write the wave equation for this conditions.

The general equation of the wave when it is traveling in +x direction is given by :


y=A\sin(kx-\omega t)

A is amplitude

k is propagation constant


k=(2\pi)/(\lambda)\\\\k=(2\pi)/(0.35)\\\\k=17.95\ m^(-1)\approx 18\ m^(-1)


\omega is angular frequency


\omega=(2\pi)/(T)\\\\\omega=(2\pi)/(1.2)\\\\\omega=5.23\ s^(-1)

So, the wave equation is given by :


y(x,t)=(0.084) \sin (18 x - 5.2 t)

Hence, this is the required solution.

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