Step-by-step explanation:
It is given that,
Object distance from the mirror, u = -30 cm
Focal length of the mirror, f = +15 cm
Size of the object, h = 7.5 cm
We need to find the image distance and the size of the image.
Mirror's formula,
![(1)/(v)+(1)/(u)=(1)/(f)](https://img.qammunity.org/2021/formulas/physics/high-school/cirv3dg4o0hv2oje53b55yonin25mr9n3b.png)
v is image distance
![(1)/(v)=(1)/(f)-(1)/(u)\\\\(1)/(v)=(1)/((15))-(1)/((-30))\\\\v=10\ cm](https://img.qammunity.org/2021/formulas/physics/high-school/843m9ah54zvhb8v8r145pudswxlnypvfqj.png)
Let h' is the size of the image. So,
![(h')/(h)=(-v)/(u)\\\\h'=(-vh)/(u)\\\\h'=(-10* 7.5)/(-30)\\\\h'=2.5\ cm](https://img.qammunity.org/2021/formulas/physics/high-school/jqby37nimpkzkqwckwepyftb4vu0l8akbt.png)
So, the image is located at a distance of 10 cm and the size of the image is 2.5 cm.