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Find the first, fourth, and eighth terms of the sequence A(n)=-3 X 2^n-1

1; –216; –279,936

–6; –48; –768

–12; –96; –1,536

–3; –24; –384

User Suresh Ram
by
4.6k points

2 Answers

6 votes

Answer: –3; –24; –384

Explanation:

User CyrilleGuimezanes
by
5.4k points
2 votes

Answer:

The answer is

3, 24, 384

Explanation:

Usng the formula


A(n) = 3(2) ^(n - 1)

Where n is the number of terms

For the first term


A(1) = 3(2)^(1 - 1) \\ = 3(2) ^(0) \\ = 3(1) \\ \\ = 3

For the fourth term


A(4) = 3(2)^(4 - 1) \\ = 3 ({2})^(3) \\ = 3 * 8 \\ \\ = 24

For the eighth term


A(8) = 3 ({2})^(8 - 1) \\ = 3 ({2})^(7) \\ = 3(128) \\ \\ = 384

Hope this helps you

User Talanb
by
5.7k points
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