Find the first, fourth, and eighth terms of the sequence A(n)=-3 X 2^n-1 1; –216; –279,936 –6; –48; –768 –12; –96; –1,536 –3; –24; –384

Question

asked Apr 17, 2021 167k views

2 Answers

Talanb · Answer 1 · 2021-04-21T14:57:10+0000

Answer:

The answer is

Explanation:

Usng the formula

A(n) = 3(2) ^(n - 1)

Where n is the number of terms

For the first term

$A(1) = 3(2)^(1 - 1) \\ = 3(2) ^(0) \\ = 3(1) \\ \\ = 3$

For the fourth term

$A(4) = 3(2)^(4 - 1) \\ = 3 ({2})^(3) \\ = 3 * 8 \\ \\ = 24$

For the eighth term

$A(8) = 3 ({2})^(8 - 1) \\ = 3 ({2})^(7) \\ = 3(128) \\ \\ = 384$

Hope this helps you