Answer:
Explanation:
Given the system of equations y=30x+10 y=and 5x²−25, since both functions are written in terms of a varaible y, we will equate the two functions to gether and firt alculate the value of x as shown;
30x+10 = 5x²−25,
Equating the expression to zero;
5x²−25-30x-10 = 0
5x²−30x-25-10 = 0
5x²−30x-35 = 0
Dividing through by 5;
x²−6x+7 = 0,
On factoring;
x = -b±√b²-4ac/2a
a = 1, b = -6 and c = 7
x = 6±√(-6)²-4(1)(7)/2(1)
x = 6±√36-28/2
x = 6±√8/2
x = 6±2√2/2
x = 3±√2
x = 3+√2 or 3-√2
Substituting x = 3+√2 into y = 30x+10
y = 30(3+√2 ) + 10
y = 10(3(3+√2)+1)
y = 10(9+1+3√2)
y = 10(10+3√2)