Answer:
Explanation:
The data given are;
sample size n = 100
sample mean x = 3.1
standard deviation σ = 0.5
mean = 3
The value for Z can be determined by using the formula:



Z = 0.2
At 95% Confidence interval, level of significance ∝ = 0.05
From the z table ;P- value for the test statistics at ∝ = 0.05
P = 0.0228
We can see that the P-value is < ∝
Decision Rule:
Reject the null hypothesis
if P-value is less than ∝
Conclusion:
At 0.05 level of significance; we conclude that the mean of the population is significantly > 3 min