Question

A school district needs to arrange transportation for at least 360 students for a field trip. The district can use large buses or small buses. The large buses hold 60 students each and have an operating expense of $300 for the day. The small buses hold 45 students each and have an operating expense of $200 for the day. The district only has chaperones for, at most, seven buses. What is the minimum cost for the transportation for the field trip if each bus has chaperones

Answer 1

1,700

Step-by-step explanation:

its on edge

Answer 2

$1700

Step-by-step explanation:

The total number of students are 360 and the best option in selecting large bus or small bus is the one with lowest cost per student.

Large bus cost per student = $300 / 60 students = $5 per student

Small bus cost per student = $200 / 45 students = $4.44 per student

This means that the small bus is the best option.

So by using hit and trail basis,

(45 students * 4 mini buses) + (60 students * 3 Large Buses) = 360 Students

As we have the limit for 7 buses, the above scenario is the best option here and the total cost for 4 mini bus and 3 large buses is as under:

Total Cost = $200 * 4 Mini Buses + $300 * 3 Large Buses

Total Cost = $800 + $900 = $1700