Question

What is the decibel level of the sound of a ticking clock with intensity 10−9 watts per square inch? Use a logarithmic model to solve.

Answer 1

30dB

Explanation:

Answer 2

β = (-0.19 dB).

Explanation:

The formula which is used to calculate the decibel level of a sound is given by :

`\beta=10\log ((I)/(I_o))`

I is intensity of the sound of a ticking clock

`I_o=10^(-12)\` watts per square meter

Since,
`1\ \text{inch}^2=(1)/(1550)\ \text{m}^2`

The intensity of a monster truck is converted into per square meter as follows:

`10^(-9)\ {W/in^2}= (10^(-9))/(1550)\ W/m^2\\\\10^(-9)\ {W/in^2}=6.45* 10^(-13)\ W/m^2`

So, Decibal level is :

`\beta=10\log ((6.45* 10^(-13))/(10^(-12)))\\\\\beta =-0.19\ dB`

So, the decibel level of the sound of a ticking clock is (-0.19 dB).