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Three resistances of 12 , 16 , and 20 are connected in parallel. What resistance must be connected in series with this combinations to give a total resistance of 25 ?
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31 votes
31 votes
Three resistances of 12 , 16 , and 20 are connected in parallel. What resistance must be connected in series with this combinations to give a total resistance of 25 ?

User Jdee
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1 Answer

9 votes
9 votes

Answer:

Total resistance in parallel is Rp

So (1/Rp) = (1/12)+(1/16)+(1/20)

Rp = ?

impedance is 25

25 = Rp + Rs

put the value of Rp you'll get the answer.

User Godheaper
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