Question

suppose that consumer usage time of computers in the public library is uniformly distributed with a minimum of 20 minutes and a maximum of 80 minutes. what is the standard deviation of the distribution

Answer 1

17.32 minutes

Explanation:

The standard deviation for a uniform distribution is:

`\sigma =(b-a)/(\sqrt12)`

If a = 20 minutes and b = 80 minutes, the standard deviation is:

`\sigma =(80-20)/(\sqrt12) \\\sigma=17.32\ minutes`

The standard deviation of the distribution of consumer usage time of computers in the public library is 17.32 minutes.