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What is the standard form of the equation for this circle?

A (x-1)2-(y + 10)² + 4 = 0
B. (x - 1)2 - +10)2 = 2
c. (x + 1)2 + (y- 1072 = 4
D. (x-1)2-(y + 10)² = ​

What is the standard form of the equation for this circle? A (x-1)2-(y + 10)² + 4 = 0 B-example-1
User Speeder
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1 Answer

3 votes

Answer:

(x + 1)² + (y - 10)² = 4

Explanation:

Standard form of the equation of a circle is given by,

(x - h)² + (y - k)² = r²

where (h, k) is the center of the circle and 'r' is the radius.

In the given question coordinates of the center A are (-1, 10) and radius of the circle is 2 units.

By substituting these values in the formula,

(x + 1)² + (y - 10)² = 2²

(x + 1)² + (y - 10)² = 4

Therefore, standard form of the equation of the given circle is (x + 1)² + (y - 10)² = 4

User MichaelsonBritt
by
5.3k points
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