Question

A generator operating at 50 Hz delivers 1 pu power to an infinite bus through a transmission circuit in which resistance is ignored. A fault takes place reducing the maximum power transferable to 0.5 pu whereas before the fault, this power was 2.0 pu and after the clearance of the fault, it is 1.5 pu. Using equal area criterion, determine the critical clearing angle.

Answer 1

critical clearing angle = 70.3°

Step-by-step explanation:

Generator operating at = 50 Hz

power delivered = 1 pu

power transferable when there is a fault = 0.5 pu

power transferable before there is a fault = 2.0 pu

power transferable after fault clearance = 1.5 pu

using equal area criterion to determine the critical clearing angle

Attached is the power angle curve diagram and the remaining part of the solution.

The power angle curve is given as

= Pmax sinβ

therefore : 2sinβo = Pm

2sinβo = 1

sinβo = 0.5 pu

βo =
`sin^(-1) (0.5) = 30`⁰

also ; 1.5sinβ1 = 1

sinβ1 = 1/1.5

β1 =
`sin^(-1) ((1)/(1.5) )` = 41.81⁰

∴ βmax = 180 - 41.81 = 138.19⁰

attached is the remaining solution

The critical clearing angle =
`cos^(-1) 0.3372` ≈ 70.3⁰