Question

A straight wire carrying a current of 7.2 A has a field of 8.9 10–3 T at right angles to it. What length of wire in the field will experience a force of 2.1 N? 2.6 10–3 m 3.1 10–1 m 1.3 10–1 m 3.3 101 m

Answer 1

33.18m

Step-by-step explanation:

the length is 3.3 x 10^1m

Answer 2

3.3x10^1m

Step-by-step explanation:

F=LIBsinθ

Force F= 2.1N

Length L = unknown

Current I= 7.2A

Magnetic field B = 8.9x10^-3

sinθ = sin90° = 1 (because the field is at right angles to the wire)

2.1 = L (7.2)(8.9x10^-3)(1)

L = 32.77m

= 3.3x10^1m