Question

Consider the function f(x) = x2 + 12x + 11. x-intercepts: 0 = x2 + 12x + 11 0 = (x + 1)(x+ 11) y-intercept: f(0) = (0)2 + 12(0) + 11 What are the intercepts of the function? The x-intercepts are . The y-intercept is

Answer 1

man up there is right

Explanation:

Answer 2

The coordinates of the x-intercepts are;

(-1, 0) and (-11, 0)

The coordinate of the y-intercept is;

(0, 11)

Explanation:

The given function is f(x) = x² + 12·x + 11

The x-intercept is at f(x) = 0 which gives;

0 = x² + 12·x + 11 which has been factored as (x + 1)(x+11) such that we have;

(x + 1)(x+11) = 0

x = -1, or x = -11

The y-intercept occurs at x = 0, we therefore have;

f(0) = (0)² + 12·(0) + 11 = 11

Therefore, we have f(0) = 11 = Y

Given that at the x-intercept, y = 0, then the coordinates of the x-intercepts are;

(-1, 0) and (-11, 0)

Given that at the y-intercept, x = 0, then the coordinate of the y-intercept is;

(0, 11).