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Calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.

[L=6.02x10^23 mol^-1] ​

User Pmann
by
9.1k points

1 Answer

4 votes

Step-by-step explanation:

  • We need to find the amount of carbon dioxide gas in
    1.505* 10^(23) molecules of the gas.
  • We know that, 1 mole weighs 44 gram of carbon dioxide which contains
    6.022* 10^(23) number of molecules. It means that,
    6.022* 10^(23) number of molecules present in 44 grams of carbon dioxide molecule. So,
    1.505* 10^(23) number of molecules present in :


=(1.0505* 10^(23))/(6.022* 10^(23))* 44\\\\=7.675\ \text{grams}

  • Hence, 7.675 grams of carbon dioxide is present in
    1.505* 10^(23) molecules of the gas.
User Darshan Patel
by
9.1k points

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