Question

Calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.

[L=6.02x10^23 mol^-1] ​

Answer 1

Step-by-step explanation:

• We need to find the amount of carbon dioxide gas in
  `1.505* 10^(23)` molecules of the gas.

• We know that, 1 mole weighs 44 gram of carbon dioxide which contains
  `6.022* 10^(23)` number of molecules. It means that,
  `6.022* 10^(23)` number of molecules present in 44 grams of carbon dioxide molecule. So,
  `1.505* 10^(23)` number of molecules present in :

`=(1.0505* 10^(23))/(6.022* 10^(23))* 44\\\\=7.675\ \text{grams}`

• Hence, 7.675 grams of carbon dioxide is present in
  `1.505* 10^(23)` molecules of the gas.