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An air-track glider of mass 0.25 kg moving at 0.60 m/s collides with and sticks to a glider of mass 0.50 kg at rest. How much kinetic energy is converted into other forms of energy as a direct result of this collision?

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Answer:

0.03 Joules have been converted into other forms of energy as the direct result of the collision.

Step-by-step explanation:

Let's start studying the conservation of momentum for the system:


P_i=P_f\\(0.25\,kg)\,{0.6\,m/s)+(0.5\,kg)\,(0\,m/s)=(0.25\,kg+0.5\,kg)\, v_f \\\\\\ 0.15\,kg\,m/s=0.75\,kg\,\,v_f\\v_f=0.15/0.75\,\,m/s\\v_f=0.2\,\,m/s

Now that we know the speed of the newly created object, we can calculate how the final kinetic energy differs from the initial one:


K_i=(1)/(2) (0.25)\,(0.6)^2+(1)/(2) (0.5)\,(0)^2=0.045\,\,J\\ \\K_f=(1)/(2) (0.75)\,(0.2)^2=0.015\,\,J\\

Then, when we subtract one from the other, we can estimate how much kinetic energy has been converted into other forms of energy in the collision:

0.045 J - 0.015 J = 0.03 J

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