Answer:
A) 0.989
B) 0.875
Explanation:
Let the X denote height measurements of ten year old children.
Thus, X follows the Normal distribution with mean = 56.2 inches and standard deviation = 3.3 inches.
A) we have to find the probability that a randomly chosen child has a height of less than 63.75 inches.
That is;
P(X < 63.75)
using z score formula, we have;
Z = (X - μ)/σ
Where, μ is mean and σ is standard deviation.
Thus;
Z = (63.75 - 56.2)/3.3
Z = 2.288
From z distribution table, we have the value as approximately 0.989
B) Similarly, using z score formula, we have;
Z = (X - μ)/σ
Where, μ is mean and σ is standard deviation.
Thus;
we have to find the probability that a randomly chosen child has a height of more than 60 inches.
Z = (60 - 56.2)/3.3
Z = 1.1515
From z-tables, the value is approximately 0.875