Question

Simplify

`\frac{3x - 12x {y}^(2) }{6 - 3y - 18 {y}^(2) }`
​

Answer 1

`(2xy+x)/(3y+2)`

Explanation:

Factor numerator and denominator and cancel common factors.

`(3x-12xy^2)/(6-3y-18y^2)=(-3x(4y^2-1))/(-3(6y^2+y-2))=(x(2y-1)(2y+1))/((2y-1)(3y+2))\\\\=\boxed{(2xy+x)/(3y+2)}`