Question

3. A particle of charge +7.5 µC is released from rest at the point x = 60 cm on an x-axis. The particle begins to move due to the presence of a charge ???? that remains fixed at the origin. What is the kinetic energy of the particle at the instant it has moved 40 cm if a) ???? = +20 µC and b) ???? = −20 µC?

Answer 1

To calculate the kinetic energy of a particle, you can use the equation Kinetic energy = (1/2) * m * v^2, where m is the mass of the particle and v is its velocity. Given the charge of the particle and the distance it has moved, you can calculate the velocity using the equation v = √((2 * q * V) / m). By substituting the given values, you can determine the kinetic energy for different charges.

Step-by-step explanation:

The kinetic energy of a particle can be calculated using the equation:

Kinetic energy = (1/2) * m * v^2

where m is the mass of the particle and v is its velocity.

In this case, we are given the charge of the particle (+7.5 µC) and the distance it has moved (40 cm).

To calculate the velocity of the particle, we can use the equation:

v = √((2 * q * V) / m)

where q is the charge of the particle, V is the potential difference, and m is the mass of the particle.

Substituting the given values, we can calculate the kinetic energy for both cases when ???? = +20 µC and ???? = −20 µC.