Question

What’s the answer of g

Answer 1

`\huge\boxed{g(a-1)=(2-a)/(a)=(2)/(a)-1}`

Explanation:

`g(t)=(1-t)/(1+t)\\\\g(a-1)-\text{substitute}\ t=a-1\ \text{to}\ g(t):\\\\g(a-1)=(1-(a-1))/(1+(a-1))=(1-a-(-1))/(1+a+(-1))=(1-a+1)/(1+a-1)=((1+1)-a)/((1-1)+a)=(2-a)/(a)`