Using the balanced equation below, how many grams of iron(iii) oxide would be required to make 187g iron Fe2O3+3CO = 2Fe+3CO2

Question

asked May 24, 2021 99.1k views

2 Answers

Viseshini Reddy · Answer 1 · 2021-05-28T15:53:10+0000

Answer:

267.14 iron oxide.

Step-by-step explanation:

Given that

Fe_2O_3+3CO = 2Fe+3CO_2

We know that molecular mass of iron-oxide = 160 g/mole.

We know that molecular mass of iron = 56 g/mole.

From the above reaction we can say that

1 mole of iron -oxide produce 2 mole of iron

160 gm of iron oxide produce 112 gm of iron

So

1 gm of iron required
(160)/(112)=1.42 gm of iron oxide

Therefore

187 gm of iron required
$1.42* = 187 = 267.14\ gm$ of iron oxide.

Therefore 187 gm of iron required 267.14 iron oxide.