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What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3.x + 14) – 3?

User Smithco
by
6.7k points

2 Answers

6 votes

Answer:

Explanation:

Given

Required

Solve for x

Open all brackets

Collect like terms

Solve fraction

Multiply both sides by 6

User Oscar Yuandinata
by
6.8k points
5 votes

Answer:


x =-24

Explanation:

Given


((2)/(3))((1)/(2)x + 12) = ((1)/(2))((1)/(3)x + 14) - 3

Required

Solve for x


((2)/(3))((1)/(2)x + 12) = ((1)/(2))((1)/(3)x + 14) - 3

Open all brackets


(2)/(3)*(1)/(2)x + (2)/(3)*12 = (1)/(2)*(1)/(3)x + (1)/(2)*14 - 3


(2 * 1)/(3 *2)x + (2 * 12)/(3)= (1 * 1)/(2 * 3)x + (1 * 14)/(2) - 3


(1)/(3)x + (24)/(3)= (1)/(6)x + (14)/(2) - 3


(1)/(3)x +8= (1)/(6)x + 7 - 3

Collect like terms


(1)/(3)x - (1)/(6)x =7 - 3 -8


(1)/(3)x - (1)/(6)x =-4

Solve fraction


(2-1)/(6)x =-4


(1)/(6)x =-4

Multiply both sides by 6


6 * (1)/(6)x =-4 * 6


x =-4 * 6


x =-24

User Gaborsch
by
6.2k points
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