Question

The reaction of perchloric acid (HClO4) with lithium hydroxide (LiOH) is described by the equation: HClO4 + LiOH → LiClO4 + H2O Suppose 100 mL of perchloric acid is neutralized by exactly 46.9 mL of 0.75 M lithium hydroxide. What is the concentration of the perchloric acid? A. 0.35 M B. 0.47 M C. 0.63 M D. 1.60 M

Answer 1

A. 0.35 M

Step-by-step explanation:

Hello,

In this case, given the volume and concentration of lithium hydroxide and the volume of chloric acid, we can compute the concentration of the neutralized acid by using the following equation:

`n_(acid)=n_(base)\\\\V_(acid)M_(acid)=V_(base)M_(base)\\\\M_(acid)=(V_(base)M_(base))/(V_(acid)) =(46.9mL*0.75M)/(100mL)\\ \\M_(acid)=0.35M`

Therefore, answer is A. 0.35 M.

Regards.