57.6k views
1 vote
Write the slope-intercept form (y=mx + b) of the blue line. Explain or show your work. Write a one sentence summary comparing the blue line to the black line. Hint: Find the y-intercept. Then count up and over (y/x) to the next point on the line to determine the slope.

1 Answer

2 votes

Answer:

Therefore, the slope-intercept form of the blue line is


y = (1 )/(2)x + 2

Comparison:

The blue and black lines both have equal y-intercept but different slopes.

The black line is steeper than blue line which means the black line has a greater slope than the blue line.

Explanation:

Please refer to the attached graph of this question where we have two straight lines.

The slope-intercept form is given by


y = mx + b

Where m is the slope of the line and b is the y-intercept.

Let us find the slope of the blue line from the points given in the graph.


(x_1, y_1) = (0,2) \\\\(x_2, y_2) = (4,4) \\\\

The slope is given by


m = (y_2 -y_1 )/(x_2 -x_1) \\\\m = (4 -2 )/(4 -0) \\\\m = (2 )/(4) \\\\m = (1 )/(2) \\\\

The y-intercept is given by


y = (1 )/(2)x + b \\\\2 = (1 )/(2)(0) + b \\\\b = 2

Therefore, the slope-intercept form of the blue line is


y = (1 )/(2)x + 2

Comparison:

The blue and black lines both have equal y-intercept but different slopes.

The black line is steeper than blue line which means the black line has a greater slope than the blue line.

Write the slope-intercept form (y=mx + b) of the blue line. Explain or show your work-example-1
User Kolaente
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories