X^2+ y^2+14x-4y+17=0 center and radius

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asked Jan 27, 2023 163k views

1 Answer

Juandaco · Answer 1 · 2023-02-01T23:25:13+0000

The answer
Center (-7 , 2)
Radius 6

Here is the solution
x (x + 14) + (y - 4) y + 17 = 0
x^2 + 14 x + y^2 + 17 = 4 y
(x + 7)^2 + (y - 2)^2 - 36 = 0
1/36 (x + 7)^2 + 1/36 (y - 2)^2 = 1

X^2+ y^2+14x-4y+17=0 center and radius

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