Write down the gradient and y-intercept of each line y=4x - 1 y= (1)/(3) x + 3 help pls​

Question

Write down the gradient and y-intercept of each line

y=4x - 1

y=

`(1)/(3) x + 3`
help pls​

Answer 1

4 and -1

1/3 and 3

Step-by-step explanation:

for y=4x-1

y intercepts where x=0 so f(0)=4*0-1=-1

y intecepts = - 1

the gradient is y2-y1/x2-x1 where y2=f(x2)=4x2-1 and y1=f(x1)=4x1-1

the gradient is 4x2-1-4x1+1/x2-x1=4 ( the coeficient of x)

for y=1/3x+3

the gradient is 1/3

y intercepts is f(0)=3

Answer 2

Equation of a line is y = mx + c

where m is the gradient

c is the y intercept

a.)

y = 4x - 1

Comparing with y = mx + c

The gradient = 4

y intercept = - 1

b.)

`y = (1)/(3) x + 3`

Comparing with y = mx + c

The gradient is 1/3

The y intercept is 3

Hope this helps you