Answer:
Tangential speed of Mass revolution is greater
Step-by-step explanation:
In the above question, we are given the following values:
Radius of Mars = 3.4 × 10^6 m
Mass of Mars = 6.4 × 10^23 kg
Mass of the sun = 2.0 × 10^30 kg at a distance of 2.3 × 10^11m.
Mar’s revolution around the sun = 687 days.
Time of Revolution = 24 hours and 37 minutes to complete one revolution.
Step 1
Find the tangential speed of rotation of Mars
Rotation of Mars = 2 × π × r
Radius of Mars = 3.4 × 10^6 m
Rotation of Mars = 2 × π × 3.4 × 10^6 m
Rotation of Mars = 21362830.044m
= 21.4 × 10^6 m
Tangential Speed of rotation for Mars = Rotation of Mars/ time
Time = 24 hrs 37 minutes
Converting to seconds = 88620s
Tangential Speed of rotation = 21.4 × 10^6 m/ 88620s
= 241.48047845m/s
= 241.5 m/s
Step 2
revolution of Mars = 2 × π × d
d = 2.3 × 10^11m.
= 2 × π × 2.3 × 10^11m = 1.45 × 10^12m
Revolution of Mars = 687 days
Converting 687 days to seconds = 59356800s
Tangential Speed of Revolution of Mars = Revolution of Mars/ times
Tangential Speed of Revolution = 1.45 × 10^12m/595356800s
Tangential Speed of Revolution = 24420m/s
Comparing the Tangential Speed of Rotation with the Tangential speed of Revolution, we can see the GREATER ONE IS THE TANGENTIAL SPEED OF REVOLUTION.