Question

Hi, can someone help me on this. I'm stuck --

Answer 1

a) Fx=-5N Fy=-5*sqrt(3) N b) Fx= 5*sqrt(3) N Fy=-5N

c) Fx=-5*sqrt(2) N Fy=-5*sqrt(2) N

Explanation:

The arrow's F ( weight) component on axle x is Fx= F*sinA and on axle y is

Fy=F*cosA

a) The x component and y component both are opposite directed to axle x and axle y accordingly. So both components are negative.

So Fx = - 10*sin(30)= -5 N Fy= -10*cos(30)= -10*sqrt(3)/2= -5*sqrt (3) N

b) Now the x component is co directed to axle x , and y component is opposite directed to axle y.

So x component is positive and y components is negative

So Fx = 10*sin(60)= 5*sqrt(3) N Fy= -10*cos(60)= -10*1/2= -5 N

c)The x component and y component both are opposite directed to axle x and axle y accordingly. So both components are negative.

So Fx = - 10*sin(45)= -5*sqrt(2) N

Fy= -10*cos(45)= -10*sqrt(2)/2= -5*sqrt (2) N