Answer:
Option A. 48°C
Step-by-step explanation:
The following data were obtained from the question:
Mass (m) = 0.3 Kg
Initial temperature (T1) = 20°C
Heat (Q) added = 35 KJ
Specific heat capacity (C) = 4.18 KJ/Kg°C
Final temperature (T2) =..?
The final temperature of water can be obtained as follow:
Q = MC(T2 – T1)
35 = 0.3 x 4.18 (T2 – 20)
35 = 1.254 (T2 – 20)
Clear the bracket
35 = 1.254T2 – 25.08
Collect like terms
1254T2 = 35 + 25.08
1.254T2 = 60.08
Divide both side by the coefficient of T2 i.e 1.254
T2 = 60.08/1.254
T2 = 47.9 ≈ 48°C
Therefore, the final temperature of the water is 48°C.