Question

Just as one dozen eggs always has 12 eggs in it, one mole of a

substance always has the same number of particles in it, 6.02 x 1023.

If you measure 27.0 g of aluminum foil, which is 1 mole of aluminum,

how many Al atoms does it contain?

Answer 1

`6.022x10^(23)atoms \ Al`

Step-by-step explanation:

Hello,

In this case, given the described concept regarding the Avogadro's number, we can easily notice that 27.0 g of aluminium foil has 6.022x10²³ atoms as shown below based on the mass-mole-particles relationship:

`27.0gAl*(1molAl)/(27.0gAl) *(6.022x10^(23)atoms \ Al)/(1molAl) \\\\=6.022x10^(23)atoms \ Al`

Notice this is backed up by the fact that aluminium molar mass if 27.0 g/mol.

Best regards.