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What is the solution of (3x+8)/(x-4) greater than or equal to=0

User Drtf
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2 Answers

6 votes

Final answer:

To solve the inequality (3x+8)/(x-4) ≥ 0, we need to find the values of x that satisfy this inequality. The solution is x ≤ 4 or x > 4.

Step-by-step explanation:

To solve the inequality (3x+8)/(x-4) ≥ 0, we need to find the values of x that satisfy this inequality. We can start by finding the critical points where the expression is equal to 0 or undefined. In this case, the expression is undefined when x = 4, so we have to exclude that value from our solution. Next, we can test some intervals to determine the sign of the expression in those intervals. For example, when x < 4, the expression is positive. Similarly, when x > 4, the expression is also positive. Therefore, the solution to the inequality is x ≤ 4 or x > 4.

User JackU
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7.8k points
1 vote

Answer:


x\le \:-(8)/(3)


x>4

Step-by-step explanation:


(3x+8)/(x-4)\ge \:0

Multiply both sides by (x - 4).


(3x+8)/(x-4) (x-4) \ge \:0(x-4)


3x+8\leq \:0


3x+8-8\leq \:0-8


3x \leq \:-8


x\le \:-(8)/(3)

Makes denominator equal to 0.


x-4=0


x = 4


-8/3 \leq x<4 doesn't work in the original inequality.


x>4 works in the original inequality.

User Skub
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8.1k points

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