140k views
4 votes
Solve for x 4 ( x + 3 ) < 3 ( x + 5 )

2 Answers

5 votes

Answer:

4x^2+9x-15<0

Explanation:

x.4(x+3)<3(x+5)

(4x)(x+3)<3x+3x5

(4x)(x+3)<3x+15

4xx+4x.3<3x+15

4x^1+1+4x3x<3x+15

4x^2+12x<3x+15

(4x^2+12x)+(-3x-15)<(3x+15)+(-3x-15x)

4x^2+9x-15<3x-3x+15-15

4x^2+9x-15<0

User Laran Evans
by
8.3k points
5 votes

Answer: x < 3

Explanation:

4(x + 3) < 3(x + 5)

4x + 12 < 3x + 15 Distributed

x + 12 < 15 Subtracted 3x from both sides

x < 3 Subtracted 12 from both sides

User Leafo
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories