140k views
4 votes
Solve for x 4 ( x + 3 ) < 3 ( x + 5 )

2 Answers

5 votes

Answer:

4x^2+9x-15<0

Explanation:

x.4(x+3)<3(x+5)

(4x)(x+3)<3x+3x5

(4x)(x+3)<3x+15

4xx+4x.3<3x+15

4x^1+1+4x3x<3x+15

4x^2+12x<3x+15

(4x^2+12x)+(-3x-15)<(3x+15)+(-3x-15x)

4x^2+9x-15<3x-3x+15-15

4x^2+9x-15<0

User Laran Evans
by
6.7k points
5 votes

Answer: x < 3

Explanation:

4(x + 3) < 3(x + 5)

4x + 12 < 3x + 15 Distributed

x + 12 < 15 Subtracted 3x from both sides

x < 3 Subtracted 12 from both sides

User Leafo
by
6.0k points
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