Answer:
11
Explanation:
We are given the expression:
![4x+ (1)/(3) y^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/x1xoeo8eotmssu2bl2e6hqbch7r5mi1exc.png)
We know that x=2 and y=3. Therefore, we can substitute 2 for x and 3 for y.
![4(2)+ (1)/(3) (3)^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/wjek2qgnxzg3ecxbkmsvh6b31kn9mildhs.png)
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
First, evaluate the exponent.
3^2 = 3*3 = 9
![4(2)+ (1)/(3) (9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/aq4m9zine7g4mc6ycsukc8wlg29943jkry.png)
Next, multiply 4 and 2.
![8+ (1)/(3) (9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ark5p4x96v5mchimxb75scr29omw2uc98g.png)
Multiply 1/3 and 9, or divide 9 by 3.
![8+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/m8euowo1w108imvn38ibnz4vgnuadl4g7d.png)
Add 8 and 3