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Determine the vertex of (f)=-×^2+50×-456

User Mdameer
by
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1 Answer

5 votes

Answer:


V_x = -(50)/(2*(-1)) =25

And for the coordinate on y we can use the function like this:


V_y = -(25)^2 +50*25 -456 =169

Then the vertex would be
V= (25,169)

Explanation:

For this problem we have the following function given:


f(x) = -x^2 +50x -456

That represent a quadratic function and the general form is given by:


f(x)= ax^2 +bx +c

For this problem a =-1 , b= 50 , c=-456 and we can find the corrdinate of the vertex in x with this formula:


V_x =-(b)/(2a)

And replacing we got:


V_x = -(50)/(2*(-1)) =25

And for the coordinate on y we can use the function like this:


V_y = -(25)^2 +50*25 -456 =169

Then the vertex would be
V= (25,169)

User Pyuntae
by
8.1k points

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