Question

A card is drawn one at a time from a

well-shuffled deck of 52 cards. In 13
repetitions of this experiment, 2 kings
are drawn. If E is the event in which
a king is drawn in the 13 trials, find
the experimental probability P(E).
P(E) =

Answer 1

2/13

Explanation:

^

Answer 2

`= (6)/(55)`

Explanation:

The computation of experimental probability is shown below:-

The Number of king in a well shuffled deck consists 52 cards which is

= 4

The Number of ways of drawing consists of 4 king in 13 repetitions which is

=
`^(13)C_4`

In 13 repetition, 2 kings are drawn by
`^(13)C_2` way

Now,

`P(E) = (^(13)C_2)/(^(13)C_4) = \frac{13 !} {(13-2) ! } / (13 !)/((13 - 4)! 4!)`

`= (13 !)/(11 !\ 2 !) / (13 !)/(9 !\ 4 !)`

`= (9 !\ 4 !)/(11 !\ 2!)`

`= (4* 3)/(11* 10)`

`= (6)/(55)`

Therefore for computing the experimental probability we simply applied the above formula.