Question

6.3 kJ of energy is required to increase the temperature of some water from 60 °C to 75 °C. The specific heat capacity of water is 4200 J per kg per °C. What is the mass of the water?

Answer 1

Mass of the water = 0.1kg is 100g

Step-by-step explanation:

Mathematically;

Quantity of heat = mass of water * specific heat capacity * temperature change

From the question, we identify the following;

Quantity of heat = 6.3 KJ

1 KJ = 1000 J, so 6.3 KJ = 6.3 * 1000 = 6300 J

Mass of water = ?

Specific heat capacity = 4200

Temperature change is the difference between the final and initial temperature. = 75-60 = 15

6300 = m * 15 * 4200

63 = m * 15 * 42

63 = 630 m

m = 63/630

m = 0.1 kg