Question

The hypotenuse of a right angle triangle is x + 6. The other two sides are 12 and x. Form an equation involving x and then solve it.

Answer 1

X=9

Solution,

AB=(perpendicular)=X

AC(hypotenuse)=X+6

CB(Base)=13

Using Pythagoras theorem,

`{h}^(2) = {p}^(2) + {b}^(2) \\ {(x + 6)}^(2) = {x}^(2) + {(12)}^(2) \\ {x}^(2) + 12x + 36 = {x}^(2) + 144 \\ 12x + 36 = 144 \\ 12x = 144 - 36 \\ 12x = 108 \\ x = (108)/(12) \\ x = 9`

Hope this helps...

Good luck on your assignment...

Answer 2

The answer is x = 9

We use Pythagoras theorem to form the equation and solve for x

That's

a² = b² + c²

where a is the hypotenuse

we get

(x + 6)² = 12² + x²

Expand

x² + 12x + 36 = 144 + x²

Group like terms

We have

x² - x ² + 12x = 144 - 36

12x = 108

Divide both sides by 9

That's

12x/12 = 108/12

x = 9

Hope this helps you.