Question

For three consecutive numbers, the sum of the first number, twice the second, and 7

less than the third is 133. What are the three numbers?​

Answer 1

a = 34

b = 34

c = 36

Explanation:

a ; b ; c = consecutive numbers =>

b = a + 1

c = a + 2

a + 2b + c - 7 = 133

a + 2(a + 1) + (a + 2) - 7 = 133

a + 2a + 2 + a + 2 - 7 = 133

4a = 133 + 7 - 4

4a = 136

a = 34

b = 34

c = 36