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Given that 8 <y< 12 and 1<x< 6, find the maximum possible value of
x+y/y-x​

User AndreaBoc
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1 Answer

3 votes

Answer:

Explanation:

y = {9, 10, 11}

x = {2, 3, 4 , 5}

Maximum value of x + y = 11 + 5 = 16

Minimum value of y -x = 9 - 2 = 7


(x+y)/(y-x)=(16)/(7)

User James Crook
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