Question

Given that 8 <y< 12 and 1<x< 6, find the maximum possible value of
x+y/y-x​

Answer 1

Explanation:

y = {9, 10, 11}

x = {2, 3, 4 , 5}

Maximum value of x + y = 11 + 5 = 16

Minimum value of y -x = 9 - 2 = 7

`(x+y)/(y-x)=(16)/(7)`