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A cylinder contains 27.0 L of oxygen gas at a pressure of 1.7 atm and a temperature of 285 K . Part A How much gas (in moles) is in the cylinder? Express your answer using two significant figures.

User NTMS
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1 Answer

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Answer:


n=2.0mol

Step-by-step explanation:

Hello.

In this case, we should use the ideal gas equation in order to compute the the moles of oxygen at the given conditions of 27.0 L, 1.7 atm and 285 K as shown below:


PV=nRT\\\\n=(PV)/(RT)=(1.7atm*27.0L)/(0.082(atm*L)/(mol*K)*285K)\\ \\n=2.0mol

Best regards.

User Krezus
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