Answer:
C2H3O2^-(aq) + H^+ —> HC2H3O2
Step-by-step explanation:
The following equation was given in the question:
Na^+ + C2H3O2^-(aq) + H^+ Cl^- —> Na^+ + Cl^- + HC2H3O2
Now, to obtain the net ionic equation, we simply cancel out the ions common to both side of the equation.
A careful observation of the equation above, shows that sodium ion, Na^+ and chloride ion, Cl^- are common to both side of the equation.
Therefore, to obtain the net ionic equation, we simply cancel out Na^+ and Cl^- from both side of the equation. This is illustrated below:
Na^+ + C2H3O2^-(aq) + H^+ Cl^- —> Na^+ + Cl^- + HC2H3O2
C2H3O2^-(aq) + H^+ —> HC2H3O2
Therefore, the net ionic equation is
C2H3O2^-(aq) + H^+ —> HC2H3O2