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Find the vertex, axis of symmetry, and y-intercept of the quadratic function.

Find the vertex, axis of symmetry, and y-intercept of the quadratic function.-example-1
User Emher
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2 Answers

7 votes

Answer:

See below ~

Explanation:

Details of Graph

  • Vertex = (4, 12)
  • Axis of Symmetry : x = 4
  • Y-intercept : -4
Find the vertex, axis of symmetry, and y-intercept of the quadratic function.-example-1
User Evanescence
by
8.9k points
0 votes

Answer:

Vertex: (4, 12)

Axis of symerty: x = 4

y - inrercept: -4

Explanation:

The vertex form of quadratic function f(x) = ax² + bx + c:

f(x) = a(x - h)² + k

(h, k) - coordinates of a vertex

h = -b/2a

k = f(h)

We have f(x) = -x² + 8x - 4 ⇒ a = -1, b = 8, c = -4.

h = -8/(2 · (-1)) = -8/(-2) = 4

k = f(4) = -4² + 8 · 4 - 4 = -16 + 32 - 4 = 12

Vertex (4, 12)

Axis of symerty = h: x = 4

y - inrercept f(0) = c: -4

User Igor Nikiforov
by
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