Question

A construction company covered 3\8 of a road which is 10km long with asphalt in the first week and covered 7\18of the road in the second week with asphalt. what length of the road remained to be covered with asphalt?​

Answer 1

2.36 km

Explanation:

First they covered 3/8 of the road, so in figures that is;

=
`(3)/(8) * 10km`

=3.75 km

The second week they covered 7/18 of the road which is;

=
`(7)/(18) * 10km`

= 3.89 km

If we combine the two distances, we get;

= 3.75 km + 3.89 km

= 7.64 km

Subtract this from the total distance and you get

= 10 km - 7.64 km

= 2.36 km

Which means 2.36 km of the road is left to be covered with asphalt.