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Students all over the United States recently took the National Science Foundation test on Biology. The mean score for girls was 150, with a standard deviation of 30. What is the approximate percentile rank for a student with a score of 180

User Figar Ali
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Answer:


z=(180-150)/(30)= 1

And if we find the probability using the normal standard distribution we got:


P(z<1)=0.841

And the the percentile would be approximately 84.1

Explanation:

For this case we define the random variable of interest as "Score for girls" and we know the following parameters:


\mu =150, \sigma =30

And we want to find the percentile for the score 180 and we can use the z score formula given by:


z=(X -\mu)/(\sigma)

And replacing we got:


z=(180-150)/(30)= 1

And if we find the probability using the normal standard distribution we got:


P(z<1)=0.841

And the the percentile would be approximately 84.1

User Eento
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