2 Answers

Lasplund · Answer 1 · 2021-12-13T10:58:37+0000

Answer:

$\sin (b^\circ)=(3)/(5)$ .

Explanation:

It is given that,

$\tan (b^\circ)=(3)/(4)$

$\cos (b^\circ)=(4)/(5)$

If a figure is dilated, then the image is similar to the figure. It means the corresponding angles of figure and image are congruent.

So, the value of sin(b°) after dilation is equal to the value of sin(b°) before dilation.

We know that,

$(\sin \theta)/(\cos \theta)=\tan \theta$

$(\sin (b^\circ))/(\cos (b^\circ))=\tan (b^\circ)$

$\sin (b^\circ)=\tan (b^\circ)* \cos (b^\circ)$

$\sin (b^\circ)=(3)/(4)* (4)/(5)$

$\sin (b^\circ)=(3)/(5)$

Therefore,
$\sin (b^\circ)=(3)/(5)$ .

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