Question

Write the inequality solution for each graph shown. Use X as the variable

Answer 1

1

2

x−

1

3

≥−

1

6

or

2

7

x≤

1

10

Explanation:

Okay, so I'm gonna start by multiplying both sides Fire lt to get rid of our, um, faction. So we have six year and 70 here we get three X minus two is much is greater than or equal to negative one. Okay. Or, um, 20 acts is less iniquity. Seven. Okay, so it's to to both sides here. So we get three x is gooder than or equal to one, and then X must be greater than or equal to 1/3. And then for here we have X must be less than or equal to 7/20. Okay, so let's go to Paula. So which one is greater than the other one? Over three is 1.33 and then 7/20 is point to be five. So we see that 7/20 is larger than from one over tree. Okay, so we want X to be greater than or equal to one over. So we're including 1/3, and we want to be greater than so we're going off to infinity. And then we have exes, Dustin, or equal to seven or 20 who were including 7/20 and we want to be glass, then seven or 20. So we're going off to negative infinity. And since we have are connected or we want the union of all for peace, that's from negative infinity to infinity.

Answer 2

Important information for solving the problem!

• When you see an open circle on the number line, this means that we must use the symbols: < or > This means that the number the open circle is on is EXCLUDED from the inequality
• Closed circles on the graph mean that the number it is on is INCLUDED in the inequality, so we use these symbols: ≤ or ≥
• When the arrow on the number line is going to the right, "x" will be 'greater than' (>) or 'greater than or equal to' (≥) the values
• When the arrow on the number line is going to the left towards the negative numbers. "x" will be 'less than' (<) or 'less than or equal' (≤) to the values.

Now that we know these things, let's write some inequalities

Answers:

3. x > -3 (x is great than negative 3)

4. x ≤ 1 (x is less than or equal to 1)

5. x ≥ 1 (x is greater than or equal 1)