Answer:
The angular acceleration of the tire is 0.454 rad/s²
Step-by-step explanation:
Given;
initial velocity, u = 3.4 rev/s = 3.4 rev/s x 2π rad/rev
u = 21.3656 rad/sec
final velocity, v = 5.5 rev/s = 5.5 rev/s x 2π rad/rev
v = 34.562 rad/sec
Calculate the value of angular rotation, θ, of the tire
θ = Number of revolutions x 2π rad/rev
θ =

θ = (260 / r)
r is the radius of the tire = 64 / 2 = 32cm = 0.32 m
θ = (260 / 0.32)
θ = 812.5 rad
Apply the following kinematic equation, to determine angular acceleration of the tire;

Therefore, the angular acceleration of the tire is 0.454 rad/s²